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Hcf of 391 425 and 527

WebThe HCF of 391, 425, and 527 is 17. ∴ The highest number that divides 391, 425, and 527 is 17. How many types of HCF are there? In short, the Highest Common Factor is expressed as H.C.F. Finding H.C.F. There are three methods of finding H.C.F. of two or more numbers. What is the HCF of 45? WebAug 25, 2024 · The largest number that will divide 398, 436 and 542 leaving remainders 7,11 and 15 respectively is (a) 17 (b) 11 (c) 34 (d) 45 Answer (a) Algorithm, 398 – 7 = 391; 436 – 11 = 425; 542 – 15 = 527; HCF of 391, 425, 527 = 17 Q.4. The sum of two irrational numbers is always (a) irrational (b) rational (c) rational or irrational (d) one Answer (a) Q.5.

HCF Using Euclid

WebFollow the below steps to find the HCF of given numbers with Euclid’s Division Lemma: Step 1: Apply Euclid’s division lemma, to a and b. So, we find whole numbers, q and r such that a = bq + r, 0 ≤ r < b. Step 2: If r = 0, b is the HCF of a and b. If r ≠ 0, apply the division lemma to b and r. Step 3: Continue the process until the ... WebAnswer: The HCF of 391, 425, and 527 by division method is 17. The highest common factor(HCF) or the greatest common factor(GCF) of two numbers is the largest among all … assist m saint malo https://trlcarsales.com

MCQ Questions for Class 10 Maths Chapter 1 Real Numbers

WebHighest common factor (HCF) of 391, 425, 527 is 17. Highest Common Factor of 391,425,527 is 17 Step 1: Since 425 > 391, we apply the division lemma to 425 and 391, … WebHCF of 391, 425, 527 using Euclid's algorithm To find the HCF of 391, 425 and 527, we will find the prime factorization of given numbers, i.e. 391 = 17 23; 425 = 5 5 17; 527 = 17 … assist majikan

HCF Calculator using Euclid Division Algorithm to give HCF of 490, …

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Hcf of 391 425 and 527

Extra Questions of Class 10 Maths Chapter 1 Real Numbers PDF …

WebMar 1, 2024 · HCF of 391 425 and 527 GCF of 391 425 and 527 3,147 views Mar 1, 2024 70 Dislike Share Save Last Night Study 48.7K subscribers Show more Last Night Study … WebClick here👆to get an answer to your question ️ Find the HCF of the following numbers, using the division method: 391, 425, 527. Solve Study Textbooks Guides. Join / Login. …

Hcf of 391 425 and 527

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WebHCF = 13. Required number = 13. Q3. Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11, and 15 respectively. Solution: Algorithm. 398 – 7 = 391, 436 – 11 = 425, 542 – 15 = 527. HCF of 391, 425, 527 = 17. Q4. A number N when divided by 14 gives the remainder 5. What is the remainder when the same number is ... Question: Among the numbers, 527, 528, 17, 543, 567, 576, 533, 547, find the HCF of 391, 425 and 527. Solution: HCF of 391, 425 and 527 is the number which equally divides 391, 425 and 527 when the remainder is zero. The number which satisfies this condition is 17. Hence, the HCF is 17. See more The answer to this question is 17. The HCF of 391, 425 and 527 using the different methods is explained accurately in this article. The … See more There are three methods to find the HCF of 391, 425 and 527: 1. Prime Factorisation 2. Long Division method 3. Listing common factors See more

WebTherefore, the LCM of 391 and 383 is 149753 and Highest Common Factor (HCF) of 391 and 383 is 1. Example 3: Find if 23, 49 and 391 are factors of 391. Solution: When we divide 391 by 49 it leaves a remainder. Therefore, the number 49 is not a factor of 391. All numbers except 49 are factors of 391. WebHCF of 391, 425 and 527 can be represented as HCF of (HCF of 391, 425) and 527. HCF(391, 425, 527) can be thus calculated by first finding HCF(391, 425) using long …

WebHence, we need to find the HCF of three numbers (398-7), (436-11) and (542-15). Hence, 398 - 7 = 391 436 - 11 = 425 542 - 15 = 527 Now, you can find the HCF (391, 425, 527) = 17 Hence, the largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is 17. Suggest Corrections 193 Similar questions WebHCF of 391, 425 and 527: Factors of 391 = 17 x 23. Factors of 425 = 5 x 5 x 17. Factors of 527 = 17 x 31. Now the highest common factor is 17. So the largest number that will divide 397, 435, 541 leaving remainder 6, 10, 14 . respectively is 17. Tutorialspoint. Updated on 10-Oct-2024 09:37:21.

WebHCF of 391, 425, 527 using Euclid's algorithm Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm. Highest common factor (HCF) of …

WebHCF of 25 and 40 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. Step 1: Divide 40 (larger number) by 25 (smaller number). Step 2: … assist malaysiaWebHCF of 391, 425 and 527 can be represented as HCF of (HCF of 391, 425) and 527. HCF(391, 425, 527) can be thus calculated by first finding HCF(391, 425) using long … assist marketWebThe given numbers are 391, 425, and 527. First, we will find the HCF of 391 and 425. So, the HCF of 391 and 425 is 17. Now, we will find the HCF of 17 and 527. So, the HCF of 17 and 527 is 17. ∴ The HCF of 391, 425, and … assist massenhovenWebThe greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 … assist marketing jobsWebCalculate GCF, GCD and HCF of a set of two or more numbers and see the work using factorization. Enter 2 or more whole numbers separated by commas or spaces. The Greatest Common Factor Calculator solution … assist merksemWebJun 6, 2012 · The HCF of two positive integers is the largest positive integer that divides both the integers. So, the required number will be the HCF of 391, 425 and 527. And that can be found by using Euclid’s division algorithm. 425 = 391 x 1 + 34 391 = 34 x 11 + 17 34 = 17 x 2 + 0 Thus, HCF = 17 Hence, the required number is 17. assist ni jobsWebSep 21, 2024 · The factors of 391 are: 1, 17, 23, 391 The factors of 425 are: 1, 5, 17, 25, 85, 425 The factors of 527 are: 1, 17, 31, 527 Then the greatest common factor is 17. hope this helps:) Find Math textbook solutions? Class 12 ML Aggarwal - Understanding Mathematics - Class 9 ML Aggarwal - Understanding Mathematics - Class 8 assist mmm